absolute R.I of water is 4/3 what is critical angle? ?
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Answered by
2
hello !!
we know that critical angle = arcsin (1/u)
here , u = 4/3
therefore..
=) critical angle = arcsin( 3/4 ) = 37° ans
we know that critical angle = arcsin (1/u)
here , u = 4/3
therefore..
=) critical angle = arcsin( 3/4 ) = 37° ans
Answered by
2
sinθ = 1/(R.I)
θ = arcsin (1/R.I)
θ = arcsin (3/4) = 48.5903⁰
θ = arcsin (1/R.I)
θ = arcsin (3/4) = 48.5903⁰
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