Question

absolute refractive indices of two media a and b are 2 and 1.5 respectively if the speed of light in medium b is 2×10^8m/s calculate the speed of light in medium a

Answer 1

v2 in medium b=2*10^8m/s and n2 of med b=1.5 and n1 of med a=2
n2=c/v2
so from here c=3*10^8m/s
n1=c/v1
we get , v1=1.5*10^8m/s=SPEED OF LIGHT IN MED a
HOPE U FIND IT EASY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

Here, nA = 2.0 ; nB = 1.5 ; vB = 2×10 8 m/s

(a) nB = c/vA

So, c = nB × vB = (1.5 × 2× 10 8) m/s

= 3×10 8 m/s

(b) nA = c/vA = (3×10 8/ 2) m/s

= (1.5×10 8) m/s