Math, asked by anubha46, 4 months ago

Abu boarded a bus at 7 in the morning. Usually the bus
travels 30 km/h on average, to reach the railway station at
11. But since it was raining, the bus could run only
20 km/h on average. Abu got down from the bus at 9,
caught a car and reached the station at 11 itself. What was
the average speed of the car?​

Answers

Answered by Anonymous
5

Answer:Let bus-A travel at a speed of 60 km/hr and bus-B travel at a speed of 90 km/hr.

 

Let both the buses meet after t hours from the starting time of bus-B.

 

Distance travelled by bus-B = 90×t  ...(1)

 

Since bus-A has already started 1 hour before bus-B, distance travelled by bus-A = 60×(t+1)  ...(2)

 

Since both are meeting , distance given in eqn.(1) and eqn.(2) are same.

 

hence 90×t = 60×(t+1)  ...(3)

 

By solving eqn.(3), we get t = 2 hour.

 

Hence the high speed bus-B will meet the earlier bus-A after 2 hour.

\huge\orange{@alurringbabe}

Answered by meghasinghal235
19

Answer:

speed of car was 40 km/h

Step-by-step explanation:

total distance = 4 hr * 30 km = 120km

distance travelled by bus = 20 * 2 = 40 km

remaining distance = 120 - 40 = 80 km

speed of car = distance/ time

= 80/2

= 40 km/h

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