Abus begins to move with an acceleration of bongA man 0.75 who is 48m behind the bus starts running at 10mg to catch the bus. The man will be able to catch the bus after IA 6 TB] 5s IC) 3s ID] 8s Correct Ans: D] 8s
Answers
Answered by
1
Answer:
Given,
Acceleration of bus, a=1ms
−2
Assume man catches the train in timet.
Displacement by man in time t s
1
=vt=10t
Displacement by bus in time t, s
2
=ut+
2
1
at
2
=
2
t
2
Separation between man and bus is 48m
s
1
=s
2
+48
10t=
2
t
2
+48
t
2
−20t+96=0
t=
2
20±
20
2
−4×96
t=8and12
In first attempt he caches the bus
Hence, minimum time he catches the bus is 8sec
Explanation:
Similar questions