Question

Abusstartingfromrestmoveswithauniformaccelerationof 0.1ms-2 for2minutes.Find(a)thespeedacquired,(b)thedistance
travelled

Answer 1

Answer:

u=0 ms-1

t=120s

a=0.1ms-2

Explanation:

(a)

v=u+at

v=0ms-1 + 0.1ms x 120

v=12ms-1

(b)by the equation

s=ut+1/2at2

s=0x120+1/2x0.1x120x120

s=720m

Answer 2

Correct Question -

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A bus starting from rest moves with a uniform acceleration of 0.1 m/s² for 2 minutes.

Find -

(a) Final Speed

(b) Distance travelled.

Answer -

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Given -

$\longrightarrow$u = 0 ( because starting from rest )

$\longrightarrow$a = 0.1 m/s²

$\longrightarrow$t = 2 min = 120 sec.

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To find -

$\longrightarrow$v ( final velocity )

$\longrightarrow$s ( distance )

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Formula used -

First equation of motion

$\longrightarrow$ v = u + at

Second equation of motion

$\longrightarrow$ s = ut + 1/2 at²

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Solution -

Using 1st equation of motion

v = u + at

$\longrightarrow$v = 0 + 0.1 × 120

$\longrightarrow$v = 12 m/s

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By 2nd equation of motion -

s = ut + 1/2 at²

$\longrightarrow$s = 0 × t + 1/2 × 0.1 × 120 × 120.

$\longrightarrow$s = 720m

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Thanks