Question

abx^2+ (b^2-ac) x-bc=0​

Answer 1

Answer:

$Given: abx2+(b2−ac)x−bc=0</p><p></p><p>Factorizing the given equation,</p><p></p><p>⟹abx2+b2x−acx−bc=0</p><p></p><p>⟹bx(ax+b)−c(ax+b)=0</p><p></p><p>⟹(bx−c)(ax+b)=0</p><p></p><p>Solving the above equation for x, we get</p><p></p><p>⟹(bx−c)=0 or (ax+b)=0</p><p></p><p>⟹x=bc or x=a−b</p><p></p><p></p><p>$

Step-by-step explanation:

please mark me as brainliest and follow me