Abx square + ( b square - ac) x- bc = 0
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Answered by
0
It is a quadratic formula. . @santhosh
tanisha38:
yes but plz can u evaluate this
Answered by
8
Hi ,
abx² + ( b² - ac ) x - bc = 0
abx² + b² x - ac x - bc = 0
bx ( ax + b ) - c ( ax + b ) = 0
( ax + b ) ( bx - c ) = 0
ax + b = 0 or bx - c = 0
ax = - b or bx = c
x = -b / a or x = c / b
I hope this helps you.
:)
abx² + ( b² - ac ) x - bc = 0
abx² + b² x - ac x - bc = 0
bx ( ax + b ) - c ( ax + b ) = 0
( ax + b ) ( bx - c ) = 0
ax + b = 0 or bx - c = 0
ax = - b or bx = c
x = -b / a or x = c / b
I hope this helps you.
:)
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