Question

abx2 = (a+b)2 × (x-1)

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$\green {x = \frac{a+b}{a}\:Or\:x = \frac{a+b}{b} }$

Step-by-step explanation:

$abx^{2}= (a+b)^{2} (x-1)$

$\implies abx^{2}- (a+b)^{2} (x-1) = 0$

$\implies abx^{2} -(a+b)^{2}x + (a+b)^{2}=0$

/* Divide each term by ab ,we get

$\implies x^{2} -\frac{(a+b)}{ab} x + \frac{(a+b)^{2}}{ab}=0$

$\implies x^{2} - \frac{(a+b)}{a} x - \frac{(a+b)}{b} x + \frac{(a+b)^{2}}{ab} = 0$

/* Splitting the middle term, we get

$\implies x\left( x - \frac{a+b}{a}\right) -\frac{(a+b)}{b} \left( x - \frac{a+b}{a}\right)=0$

$\implies \left( x - \frac{a+b}{a}\right)\left( x - \frac{a+b}{b}\right) = 0$

$\implies x - \frac{a+b}{a}=0 \:Or \: x - \frac{a+b}{b} = 0$

$\therefore x = \frac{a+b}{a}\:Or\:x = \frac{a+b}{b}$

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