abx²+(ay-b)x-y factorise the following
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(bx+y) (ax-y)
abx²+(ay-b)x-y
abx²+ayx-bx-y
abx²-bx+ayx-y
bx(ax-1)+y(ax-1)
(bx+y) (ax-1)
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Answer:
abx^2+(ay-b)x-y
=abx^2+ayx-bx-y
=ax(bx+y)-1(bx+y)
=(bx+y)(ax-1)
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