Question

abx² +(b²-ac)x-bc =0
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Answer 1

Factorizing the given equation,

⟹abx^2 +( b^2 -ac) x - bc = 0

⟹bx(ax+b)−c(ax+b)=0

⟹(bx−c)(ax+b)=0

Solving the above equation for x, we get

⟹(bx−c)=0 or (ax+b)=0

solving this we get

bx-c = 0

bx= c

x= c/b

and

ax+b = 0

ax= -b

x= -b/ a

hence x= c/b and x= -b/a

hope it helps

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