AC=29 CD=21 find perimeter of rectangle answer is 82
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AC=29
CD=21 (B)
AC^2= CD^2 + AD^2
29^2 = 21^2 + AD^2
841 - 441 = AD^2
400 = AD^2
AD = 20 (L)
perimeter of rectangle = 2 ( L + B) = 2 (20 + 21)
= 2 (41) = 82
PLEASE SELECT MY ANSWERS AS BRAINLIEST
CD=21 (B)
AC^2= CD^2 + AD^2
29^2 = 21^2 + AD^2
841 - 441 = AD^2
400 = AD^2
AD = 20 (L)
perimeter of rectangle = 2 ( L + B) = 2 (20 + 21)
= 2 (41) = 82
PLEASE SELECT MY ANSWERS AS BRAINLIEST
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