Question

Ac=41 and Bc = 4 find third side by pyathagoras therom ​

Answer 1

here AC=41,BC=4,AB=?
by pyathagoras theram
AC^2=AB^2+BC^2
41^2=AB^2+4^2
AB^2=1681-16
AB^2=1665

by taking square root
AB=40.80


third side is 40.80

Answer 2

By Pythagoras theorem, In triangle abc right angled at B,

AC^2=AB^2+BC^2, let AB=x

41*41=x^2+4*4

1681=x^2+16

X^2=1681-16

X^2=1665

X=root1665

X=40.80.

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