ac=95 ab=15x-10 bc=5x+5
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What we have to find.......
itsjustme7611:
point b is between a and c on ac line. find the values of x, ab, and bc
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ac= 95 = 5×19
a= 5
c=19
5x+5= 19b ...….. × 3
15x-10 =5b
25=33b
b=25/33
a=5 ,b= 25/33 ,c=19
ac= 95= 19×5
a= 19 & c=5
19b= 15x-10
5b. = 5x+5
75x-50=
19b = 15x -10
15b = 15x +15
4b= -25
b= -25/4
a= 19,b= -25/4 & c=5
a= 5
c=19
5x+5= 19b ...….. × 3
15x-10 =5b
25=33b
b=25/33
a=5 ,b= 25/33 ,c=19
ac= 95= 19×5
a= 19 & c=5
19b= 15x-10
5b. = 5x+5
75x-50=
19b = 15x -10
15b = 15x +15
4b= -25
b= -25/4
a= 19,b= -25/4 & c=5
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