Question

AC
A, C, with, \overleftrightarrow, on top is tangent to circle OOO at point CCC.
What is the measure of \angle ACO∠ACOangle, A, C, O?
^\circ
∘
degrees


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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Your question was incomplete. Please check the content below:

'O' is a centre of a circle, AC is a tangent to a circle at point A. If ΔOAC is an isosceles triangle, then find the measure of  ∠OCA

(A) 75°

(B) 50°

(C) 45°

(D) 40°

Answer:

Option (C) 45°

Step-by-step explanation:

A circle is a figure that has no sides and no vertices.

It has a radius and a centre. The centre is the point from which all the other points on the circle are equidistant and the distance is equal to the radius.

Let AC = tangent to circle of centre O.

OA ⊥ AC         ...(∵ Radius is always perpendicular to the tangent)

∴ ∠OAC = 90° and ΔOAC is isosceles triangle ( given)

∴∠O=∠C=x

Now, by angle sum property of triangle. We have that :

90° + x + x= 180°

So, we get that:

⇒x=45°

Therefore, we get that the value of  ∠OCA=45°.

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