AC
A, C, with, \overleftrightarrow, on top is tangent to circle OOO at point CCC.
What is the measure of \angle ACO∠ACOangle, A, C, O?
^\circ
∘
degrees
Answers
Answer:
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Step-by-step explanation:
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Your question was incomplete. Please check the content below:
'O' is a centre of a circle, AC is a tangent to a circle at point A. If ΔOAC is an isosceles triangle, then find the measure of ∠OCA
(A) 75°
(B) 50°
(C) 45°
(D) 40°
Answer:
Option (C) 45°
Step-by-step explanation:
A circle is a figure that has no sides and no vertices.
It has a radius and a centre. The centre is the point from which all the other points on the circle are equidistant and the distance is equal to the radius.
Let AC = tangent to circle of centre O.
OA ⊥ AC ...(∵ Radius is always perpendicular to the tangent)
∴ ∠OAC = 90° and ΔOAC is isosceles triangle ( given)
∴∠O=∠C=x
Now, by angle sum property of triangle. We have that :
90° + x + x= 180°
So, we get that:
⇒x=45°
Therefore, we get that the value of ∠OCA=45°.
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