Question

AC= AD AND AB BISECTS ANGLE A. SHOW THAT TRIANGLE ABC CONGURENT TRIANGLE ABD.. ans- AC=AD( GIVEN) AB bisects ANGLE A (given) TRIANGLE ACB= ADB(BY SAS) AD=AD(COMMON) TRIANGLE ABC CONGRUENT TRIANGLE ABD

Answer 1

in ▲ABC & ▲ABD
Given:AB is bisetor of <A & AD=AC
proof:AC=AD (given)
<DBA=<CBA (AB IS BISECTOR OF <A)
AB=AB (COMMON)
▲ACB =▲ADB ( BY SAS)