Question

AC = AE, AB = AD and angleBAD= angleEAC. Show that BC =DE.
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Answer 1

Given: AC = AE , AB = AD , ∠BAD = ∠EAC

To prove: BC = DE

Proof:

In ΔABC and ΔADE

∠BAD = ∠EAC

AB = AD

AC = AE

∴ ΔABC ≅ ΔADE (by S.A.S side angle side)

Thus, BC = DE (corresponding parts of congruent triangles are equal)

Hence proved.//

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Answer 2

Answer:

Answer is in the pic Hope it helps you