Question

AC = AF, AB =AD and /_BAD=/_EAC
prove that BC=DE​

Answer 1

Step-by-step explanation:

Consider Triangle ABC and Triangle ADE

Given,

AB = AD

AC = AE

Angle BAD = Angle EAC

angle DAC is between both angle, so this angle is common.

so , Angle BAC = Angle DAE

Consider Triangle ABC and Triangle ADE

AB = AD ...........(given)

AC = AE ............(given)

Angle BAC = Angle DAE ............(proved)

so, by SAS C.C.,

it is proven that ,

Triangle ABC = Triangle ADE

So, by CPCT BC = DE .

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