Ac and bd intersect at e if angle abd=anglebdc and cd =4ab.Show that bd=5be
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Step-by-step explanation:
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➡ABD=BDC (given)
➡AEB=DEC (vertically opposite angle)
➡Therefore ∆ABE similar ∆DEC
(AA similarity)
➡therfore, AB/CD=BE/DE---------------1.) [corresponding sides of similar triangles are in proportion]
its given that CD=4AB ➡AB/CD=1/4
Substitute the value of AB/CD=1/4 in equation 1.)
we get,
1/4=BE/DE ➡DE=4BE
➡(BD-BE)=4BE
Or BD= 5BE
HOPE IT HELPS YOU....
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