Question

(ac+bd)^2-(ad-bc)^2 factorised

Answer 1

here is ur ans mate


we will use identity here

(ac+bd-ad-bc) (ac+bd+ad+bc)


hope it helps u

Answer 2

a²c²+b²d²+2abcd-(a²d²+b²c²-2abcd)

a²c² +b²d²+2abcd-a²d²-b²c²+2abcd

a²c²-a²d²-b²c²+b²d²+4abcd

a²(c²-d²)-b²(c²-d²)+4abcd

[(c²-d²)(a²-b²)]+4abcd


is it clear



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