AC=_______ cm
Area of Triangle ACD = ____ sq cm
Therefore area of quadrilateral ABCD=_________sq cm
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refer to above attachment.
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Consider ΔABC,
Area of the the triangle = 1/2×AC×BE = 45cm²
AC = 45×2/6 = 15cm
Area of triangle ACD = √s(s-a)(s-b)(s-c) = √21(6)(8)(7)
= √7×3×3×2×2×2×2×7 = 7×3×2×2 = 42cm²
Area of quadrilateral ABCD = 42+45 = 97cm²
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