Question

AC is a tangent to the circle with center O at point A. Triangle OAC is an isosceles triangle than angle OCA ? Sorry i don't have the diagram I will mark you the brainliest, please answer

Answer 1

Step-by-step explanation:

Let AC be the tangent to circle of centre O.

OA ⊥ AC ...(∵ Radius always ⊥ to tangent)

∴ ∠OAC = 90

o

and ΔOAC is isosceles triangle

∴∠O=∠C=x

Now, by angle sum property of Δ. We have

90

o

+x+x=180

o

⇒x=45

o

Hence, ∠OCA=45

o

Answer 2

Answer:

Answer = 90°

I hope it's help you☝️

Step-by-step explanation:

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