AC is one of the diagonals of a quadrilateral ABCD. if BP is perpendicular to AC and DQ is perpendicular to AC, show that area(quad. ABCD) = 1/2 AC x (BP + DQ).
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Answered by
6
simple question just use the formula of area of triangle to get the answer
Answered by
15
hi friend
here's your answer looking for
ar(ABCD)=ar(triangleABC) + ar(triangle ADC)
=(1/2×AC×BP) + (1/2×AC×DQ)
=1/2×AC×(BP+DQ)
hence, proved.
hope it's helpful to you.
so, plz mark it as brainliest
From brainly star Amaytripathi19
here's your answer looking for
ar(ABCD)=ar(triangleABC) + ar(triangle ADC)
=(1/2×AC×BP) + (1/2×AC×DQ)
=1/2×AC×(BP+DQ)
hence, proved.
hope it's helpful to you.
so, plz mark it as brainliest
From brainly star Amaytripathi19
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