AC is one of the diagonals of qudrilateral
ABCD. BM and DN are the altitudes
on AC from B and D respectively. If
AC = 18 cm, BM = 10 cm and DN = 6 cm,
then ar (ABCD) = .........
... cm.
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Answer:
Area of quadrilateral is 144 cm2.
Step-by-step explanation:
Area of ∆ ABC
Base = AC = 18 cm
Height = BM = 10cm
Area of ∆ABC = 1/2 ×B × H
= 1/2 × AC × BM
= 1/2 × 18 × 10
= 90 cm2
Area of ∆ADC
Base = AC = 18cm
Height = DC = 6 cm
Area of ∆ADC = 1/2 × AC × DN
= 1/2 × 18 × 6
= 54 cm2
Therefore
Area of quadrilateral ABCD = Area of ∆ ABC + Area of ∆ADC
= 90 +54
= 144 cm2
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