Ac is the diameter of a circum circle of triangle abc. Chord ed is parallel to the diamerer ac. If cbe=50, then the measure of dec
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Answer:
∠CBE = 50°
∠BAC + ∠BCA = 90° [∵ ∠ABC = 90°]
∠ABE = 90° – 50° = 40°
∴ ∠ABE = ∠ACE = 40°
∴ ∠ACE = ∠DEC = 40°
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