aC2H5OH + bO2 leads to cCo2 + dH2O
balance the equation and find the ratio of b:c after balancing
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Balanced equation is as follows: C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
The ratio of b:c = 3:2
- The steps for balancing the chemical equation are as follows.
- Write the unbalanced equation
- Consider C₂H₅OH, there are two carbons on the left side but on the right side we have only two carbons
- So let us take c to be 2, Now both sides have an equal number of carbons.
- C₂H₅OH + bO₂ → 2CO₂ + dH₂O
- On the left side, we have 6 Hydrogens, but on the left side, we have 2 Hydrogens only.
- C₂H₅OH + bO₂ → 2CO₂ + 3H₂O
- So let us take d to be 3 so that both sides have the same number of hydrogen.
- Now left side has 3 oxygen in total, but on the right, we have 7 oxygen atoms.
- To equalize both values b should be 3.
- Now we have the balanced equation
- C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
- We have to find the ratio of the stoichiometric coefficient of an oxygen molecule to a carbon dioxide molecule
- Which is b:c = 3:2
- #SPJ2
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