âcalculate the no. of atoms in 1) 0.5 mole atoms of carbon 12, (2) 18g of glucose (3) 0.20 mole molecules of oxygen?
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1:1mole-6.023*10power23,
0.5mole-3.012*10power23,
2:c6h12o6=24atoms
1mole-6.023*10power23
0.1mole-6.023*10power22.
3:1mole-2*6.023*10power23
0.20mole-2.4*10power23
0.5mole-3.012*10power23,
2:c6h12o6=24atoms
1mole-6.023*10power23
0.1mole-6.023*10power22.
3:1mole-2*6.023*10power23
0.20mole-2.4*10power23
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