Acan do a certain job in 25 dayswhich can b alone in 20 days.A started the work and was joined by B after 10days . In how many days was the whole work completed?
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acc to the que
A alone can do 1/25 of the work in 1 day
and B alone can do 1/20 of the work in 1 day
now if both of them work together
tgey can do 1/25 + 1/20 = 45/500 of the work in 1 day
since A worked alone for 10 days thus he completed 10/25 of the work ie. 200/500 of the work
now remaining 300/500 of work is to be done by both of them
so 300/500 × 45/500 = 20/3 days
so total days = 10 + 20/3 = 16.67 days
hope your query is solved !
acc to the que
A alone can do 1/25 of the work in 1 day
and B alone can do 1/20 of the work in 1 day
now if both of them work together
tgey can do 1/25 + 1/20 = 45/500 of the work in 1 day
since A worked alone for 10 days thus he completed 10/25 of the work ie. 200/500 of the work
now remaining 300/500 of work is to be done by both of them
so 300/500 × 45/500 = 20/3 days
so total days = 10 + 20/3 = 16.67 days
hope your query is solved !
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