Acar start from rest and acquiresa velocity of 54 km/h in 2 sec. Find
(i) the acceleration
(ii) distance travelled by car.Assume motion of car is uniform?
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Explanation:
U (initial velocity)= 0. (as car starts from rest)
v (final velocity)= 54km/hr = 15m/sec
time = 2 mins = 120 sec
(1) acceleration = v-u/t
=> 15 - 0/120
=> 15/120
=> 0.125 m/s²
(2) using third equation of motion
=>2as = v²-u²
=>2(0.125×s) = (15)² - (0)²
=>0.25×s=225
=>s = 225/0.25= 900m
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