Acart of mass 50 kg is moving on a straight track witha speed of 12m/s.A mass of 10 kg is gently put into the cart. what will be tge velocity of the cart after this?
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GivEn:-
- Mass of a cart = 50kg
- Speed at which cart is moving = 12m/s
- Mass gently put into the cart = 10kg
To find:
- velocity of the cart after this?
SoluTion:-
• Let's 50kg mass of a cart be M.
• Let's 12m/s speed at which cart is moving be V.
• Let's 10kg mass that gently put into the cart be m.
• Let's velocity of cart after this be v.
★ According to Law of conservation of momentum (Newton's second law) :-
As we know that,
Momentum is Mass × Velocity
Therefore,
=> MV = mv
=> 50 × 12 = (50 + 10) + v
=> 600 = 60 × v
=> 600/60 = v
=> 10 = v
Hence, Velocity of cart afer putting 10kg mass is 10 m/s.
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Answered by
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Explanation:
✴️ANSWER✴️
mass of car = 50kg
Speed = 12 m/s
After putting 10 kg mass,
Mass of car = 60kg
Let velocity be X
Since, momentum before collision = momentum after collision
50*12 = 60x
= 60x = 50*12
= X = 50*12/60
So, X = 10 m/s
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