ACB is an arc of the circle with centre 0. If AO = OB = 5.6 cm
and <AOB= (3π/4)c , determine the length of the arc ACB.
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(D) 230° m∠ACB = 1/2 m(arc AB) [Inscribed angle theorem] ∴ m(arc AB) = 2 m∠ACB = 2 × 65 = 130° m(arc ACB) = 360° – m(arc AB) [Measure of a circle is 360°] = 360° – 130° = 230°
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