ACB n(A) = 4, n (13) =) the
n (A-B) = 2
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Solution:-
We have to find out the 12th term of an AP from the end.
So, we have to assume that the last term is the first term and the last term in this AP is -100.
let the first term be -100 and d = 2
Step-by-step explanation:
a₁₂ = {a + (n-1)d}
= {100 + (12-1)2}
= (-100 + 11 × 2)
= -100 + 22
= - 78
So, the 12th term of the AP from the end will be -78
Hope it helps
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