Question

Accelaration 6 m/s . What distance will it cover in 20 second after the start

Answer 1

Given ,

u ( initial velocity ) = 0 m/s

a = 6 m/s^2

t = 20 s

:. s = ut+1/2at^2
= 0×20 + 1/2×6×20^2 m
= 0 + 3×400 m
= 1200 m

Hence the distance covered is 1200 m

Answer 2

Hii. ....friend

The answer is here,

$acceleration = 6m. {s}^{ - 2}$

Time =20 sec.

Initial velocity = 0.

$s = ut + \frac{1}{2} a {t}^{2}$

$s \: = 0(20) + \frac{1}{2} (6) {(20)}^{2}$

$= > \: s = 3 \times 400$

=> s =1200m.

So, The total distance travelled is 1200m.

:-)Hope it helps u.