Question

Acceleration a=2t+4t^2
Calculate position of object from orgin at t=4s .
(At t=0,v=0,x=0)

Answer 1

Answer:

Explanation:

Given equation,

a = 2t + 4t²

Multiplying both the sides by dt.

a.dt = (2t + 4t²).dt

⇒ Now, Integrate both the sides of the Equation,

v = t² + 4/3t³

Now, again multiplying both the sides by dt.

v.dt = (t² + 4/3t³).dt

Again Integrating both the sides of the equation,

S = t³/3 + t⁴/3

At t = 4 seconds,

S = 64/3 + 256/3

⇒ S = 21.33 + 85.33

∴ S = 106.67 m.

Hence, Displacement of the body is 106.67 m at t = 4 seconds.

Answer 2

a particle experience a constant acceleration for 6 seconds after starting from rest if it travels a distance d1 in the first two seconds , d2 in the next two seconds and a distance d3 in last 2 seconds, then