Physics, asked by anjalijoshi7249, 8 months ago

acceleration(a) varies with time(t) expression is given as a=pt^2+qt+r where p, q, r are constants.
find the dimensions of p, q and r

Answers

Answered by CosmicLad
1

Explanation:

11th

Physics

Motion in a Straight Line

Acceleration

The acceleration a of parti...

PHYSICS

The acceleration a of particle varies with time t as shown. Find an expression for velocity in terms of t. Given velocity is zero at t=0.

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ANSWER

y=mx+c

a=mt+c

For t=1 0=m+c

For t=0 −2=0+c

c=−2

a=2t−2

dt

dv

=2t−2

dv=(2t−2)dt

v∣

0

v

=t

2

−2t∣

0

t

=t

2

−2t−(0)

2

+2(0)=t

2

−2t

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