Question

Acceleration acting on the body between A and B.
6.67m/s²
7.2m/s2
2m/s
3.67m/s​

Answer 1

Answer:

The acceleration acting on the body between A and B is 6.67 m/s²

Explanation:

• Acceleration is the rate of change of velocity.

• In the velocity - time graph; where velocity is represented on y - axis and time on x - axis, the slope of the line is the rate of change of velocity.

   $\boxed{\tt Slope=\dfrac{\triangle v}{\triangle t}}$

So, the acceleration acting on the body between A and B is the slope of the line AB.

 

At A,

velocity = 20 m/s

time = 0 sec

At B,

velocity = 40 m/s

time = 3 sec

The required acceleration is

 $\longrightarrow \sf \dfrac{40-20}{3-0} \\\\ \longrightarrow \sf \dfrac{20}{3} \\\\ \longrightarrow \sf 6.67 \ m/s^2$

Therefore, the acceleration acting on the body between A and B is 6.67 m/s²