Question

. Acceleration = b/t + ct² is dimensionaly correct , where t is time calculate dimension of b & c.​

Answer 1

Answer:

Here is your answer

Explanation:

• a=b/t +ct^2

Dimension of a is [MT^-2]

So "b/t" and "ct^2" should individually have the same dimensions

Hence,

Dimension of b is [MT^-1]

Dimension of c is [MT^-4]