Question

Acceleration due to gravity at Earth's surface is 10ms ^2. The value of acceleration due to gravity at the surface
of a planet of mass (1/5) and radius (1/2) of the earth is​

Answer 1

Explanation:

g=GM/R*2

/. /

g' GM4/R*2 5

So finally answer g5/4

Thank you for you

Answer 2

The general formula to be used in this problem is

g=(GM)/R ²

• g=acceleration due to gravity(9.8 m/s²)
• G=gravitational constant(6.6738*10power-(11) Nm square/kg square)
• M= mass(Eg. Planet)

• R=Radius of object(Planet)

Now try to solve this dude..

You can do it