Question

Acceleration due to gravity at earth surface is 10m/s2 the value of acceleration due to gravity at the surface of a planet of mass 1/5th and radius 1/2 of the earth is

Answer 1

Answer:

This is the answer

F = Gm1m2/r2 = ma

Gm/r2 = g

m = gr2/G

m = (9.8 m/s2)(6.37 × 106 m)2/(6.673 × 10−11 Nm2/kg2)

m = 5.96 × 1024 kg