Acceleration due to gravity c programs stack overflow
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The acceleration which is gained by an object because of the gravitational force is called its acceleration due to gravity. Its SI unit is m/s2. Acceleration due to gravity is a vector, which means it has both a magnitude and a direction. The formula is ‘the change in velocity= gravity x time’ The acceleration due to gravity at the surface of Earth is represented as g. It has a standard value defined as 9.80665 m/s2.[1]
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Why heavier objects do not fall faster than lighter objectsEdit
Isaac Newton worked out that resultant force equals mass times acceleration, or in symbols, {\displaystyle F=ma}. This can be re-arranged to give {\displaystyle a={\frac {F}{m}}\ }. The bigger the mass of the falling object, the greater the force of gravitational attraction pulling it towards Earth. In the equation above, this is {\displaystyle F}. However, the amount of times the force gets bigger or smaller is equal to the number of times the mass gets bigger or smaller, having the ratio remain constant. In every situation, the {\displaystyle {\frac {F}{m}}\ } cancels down to the uniform acceleration of around 9.8 m/s2. This means that, regardless of their mass, all freely falling objects accelerate at the same rate.
Consider the following examples:
{\displaystyle a={\frac {49\,\mathrm {N} }{5\,\mathrm {kg} }}\ =9.8\,\mathrm {N/kg} =9.8\,\mathrm {m/s^{2}} }
{\displaystyle a={\frac {147\,\mathrm {N} }{15\,\mathrm {kg} }}\ =9.8\,\mathrm {N/kg} =9.8\,\mathrm {m/s^{2}} }
Contents
Why heavier objects do not fall faster than lighter objectsEdit
Isaac Newton worked out that resultant force equals mass times acceleration, or in symbols, {\displaystyle F=ma}. This can be re-arranged to give {\displaystyle a={\frac {F}{m}}\ }. The bigger the mass of the falling object, the greater the force of gravitational attraction pulling it towards Earth. In the equation above, this is {\displaystyle F}. However, the amount of times the force gets bigger or smaller is equal to the number of times the mass gets bigger or smaller, having the ratio remain constant. In every situation, the {\displaystyle {\frac {F}{m}}\ } cancels down to the uniform acceleration of around 9.8 m/s2. This means that, regardless of their mass, all freely falling objects accelerate at the same rate.
Consider the following examples:
{\displaystyle a={\frac {49\,\mathrm {N} }{5\,\mathrm {kg} }}\ =9.8\,\mathrm {N/kg} =9.8\,\mathrm {m/s^{2}} }
{\displaystyle a={\frac {147\,\mathrm {N} }{15\,\mathrm {kg} }}\ =9.8\,\mathrm {N/kg} =9.8\,\mathrm {m/s^{2}} }
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