Question

Acceleration due to gravity on the planet a is 9 times the acceleration due to gravity on planet



b. A man jumps to a height of 2 m on the surface of



a. What is the height jumped by the same person on the planet b?

Answer 1

Suppose u is the max speed with which the man can jump

v^2-u^2=2gA*hA

max height will be zero,hence,v^2 will be zero

-u^2=2gA*hA-----1

v^2-u^2=2gB*hB

max height here will also be zero

-u^2=2gB*hB-----2

Combining eq.1 and eq.2 we get:-

2gA*hA=2gB*hB

Since,gA=9gB

18gB*hA=2gB*hB

9hA=hB

9*2=hB(hA=2---given)

hB=18m(ANSWER)