Question

Acceleration formula in terms of velocity and distance

Answer 1

• acceleration = distance up on velocity/ time taken ...

Answer 2

as we know .

v = u + at

v- u / a = t .............1.

put value of eq.1. in formula

s = ut + 1/2 at^2

s = u ( v - u / a ) + 1/2 a ( v - u / a ^2 )

s = 1/2 a ( v - u / a ) ^ 2 + u ( v - u / a )

in the underlined ___ identity (a-b)^2 = ( a^2 + b^2 -2 ab ) will be used.

s = 1/2 a ( v ^2 + u ^2 - 2vu /a^2) + u (v - u /a)

taking l.c.m of underlined —-__

s = 1/2 a ( v^2 + u ^2 - 2vu / a ^2 ) + ( uv - u ^2 / a )

the underlined a will be cut off as these are in mmultiplication with each other

s = 1/2 ( v^2 + u^2 - 2vu / a) + uv - u ^2 / a )

multiplying 1/2 with underlined______we get

s = ( v^2 + u ^2 - 2 vu / 2a ) + ( uv - u ^2 /a )

now taking l.c.m of the equation ...we get

s = ( v^2 + u^2- 2vu + 2vu - 2 u ^2. / 2a )

s = ( v^2 + u^2 + 0 vu - 2 u ^2. / 2a)

s = ( v^2 + u^2 - 2u^2 / 2a)

subtracting : u^2 - 2u ^2 = - u^2

s = ( v^2 - u^2 / 2a)

2as = v^2 - u^2

v^2 - u^2 = 2 as

hope u understand mate please appreciate my hardwork BRainliest mark please dear❤❤