acceleration of 1,4.
7.
A 500 kg horse pulls a cart of mass 1500 kg along a level road with an
coefficient of sliding friction is 0.2, then force exerted by earth on horse is
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Answer:
Given that,
Mass of horse = 500 kg
Mass of cart = 1500 kg
Acceleration = 1 m/s2
Friction coefficient = 0.2
Now, the force by the horse
Net force in forward direction = Accelerating force + friction
F=ma+μmg
Now, put the value
F=m(a+μg)
F=(1500)(1+0.2×10)
F=1500×3
F=4500N
Hence, the force exerted by the horse in forwarding direction is 4500 N.
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