Math, asked by DrShweta2627, 10 months ago

acceleration of 12t - t³​

Answers

Answered by dhivyaarai
3

Answer:

resolving vectors:

12t-t^3

12-t^2 m/s^2

Answered by shrutika24
2

Step-by-step explanation:

as you haven't mentioned that whether 12t-t^3 is displacement or speed..

so let 12t-t^3 be speed(v) function of time

let a= acceleration

a= dv/dt

a= d(12t-t^3)/dt

a= 12- 3t^2

  • differentiation of 12t= 12
  • as dv^n/dt = (n)t^(n-1)

hope this answer helps you!!

plz mark it as brainliest..

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