acceleration of 12t - t³
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Answered by
3
Answer:
resolving vectors:
12t-t^3
12-t^2 m/s^2
Answered by
2
Step-by-step explanation:
as you haven't mentioned that whether 12t-t^3 is displacement or speed..
so let 12t-t^3 be speed(v) function of time
let a= acceleration
a= dv/dt
a= d(12t-t^3)/dt
a= 12- 3t^2
- differentiation of 12t= 12
- as dv^n/dt = (n)t^(n-1)
hope this answer helps you!!
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