Question

acceleration of 2-5t+6t²​

Answer 1

X = 2 - 5t + 6t^2

V =dX/dt = -5 +12 t(velocity)

A = dV/dt = 12(acceleration)

Initial velocity (I.e t=0) V = -5

This is way to find velocity in mathematical way

Initial velocity

As time goes on v become positive

And acceleration is always constant throughout motion(independent of time)