Acceleration of a body is given by the equation
a = (4 - 3v) m/s2. Speed v is in m/s and t is in
second. If initial velocity is zero then terminal
velocity of the body is
(1)4/3
(2)3/4
(3) 4 m/s
(4) Infinite
Answers
Answered by
13
Answer:
4/3
Explanation:
we know that
a =dv/dt
dv=(4-3v)dt
dv/(4-3v)=dt
by integration...
[-1/3log(4-3v)] 0 to v = t
1/3log(4/4-3v) = t
for terminal point t = infinite
4/4-3v = infinite
4-3v = 0
v(terminal) = 4/3
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