Acceleration of a particle having charge ‘q’ and mass ‘m’ through an electric field E is:
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Answer:
The accelaration of that charged particle is given by a=qvB/m
Explanation:
we have F=qvB that is Force on the charged particle but F=ma by Newton's second law of motion therefore
ma=qvB which gives a=qvB/m
where q is the charge, V is the velocity of the charged particle and Bis the magnetic field please mark me as brainliest and follow me
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