Question

Acceleration of a particle in SHM at displacement x=10 cm (from the mean position is a =-2.5 cm//s^(2)). Find time period of oscillations.

Answer 1

Explanation:

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Answer 2

Here the system is simple harmonic motion that SHM.

• Given the displacement x=10 cm, and a= -2.5 m/s
• The relation is
• T=2π√$\frac{x}{a}$ there is mode of the both quantities therefore in positive mode.
• Putting the values in it we get T=4π sec.
• There is more important fact in this that period and frequency are independent of the amplitude of the system.