Physics, asked by sudhanagpal8055, 10 months ago

Acceleration of a particle in x-y plane varies with time as a=(2t hati+3t^2 hatj) m//s^2 At time t =0, velocity of particle is 2 m//s along positive x direction and particle starts from origin. Find velocity and coordinates of particle at t=1s.

Answers

Answered by bajpaigori1987

0

Answer:

city velocity and coordinate are same

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