Acceleration.
of a particle starting
from rest is a = (5t) m
it's velocity
then
at t= 2 is
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Answered by
0
Answer:
Correct option is
A
15m/s
correct answer is A.
a=2(t−1)
=2t−2
dt
dv
=2t−2
dv=(2t−2)dt
integrating both side we get,
∫dv=∫(2t−2)dt
v=t
2
−2t+c
=(5)
2
−2×5
=25−10
=15m/s
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