Question

Acceleration of a particle varies with time as a = 12t2 m/s2. If the particle starts its motion from rest, then its displacement in initial 2 seconds will be

Answer 1

Answer:

Given that,

Height = 40 m

Time t =2 sec

We know that,

v=u+gt

v=0+9.8×2

v=19.6m/s

The speed of stone is 19.6 m/s

Now, the speed with which the stone strikes the ground

v

2

=u

2

+2gs

v

2

=0+2×9.8×40

v

2

=784

v=28m/s

Hence, the speed with which the stone strikes the ground is 28 m/s

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